Posts Tagged ‘CTE’

The Problem

I had a list of different routes and stops along the route (for the benefit of this example they are called seq). What I wanted to do was get the start time and the end time for each journey and so work out the journey times.
Each journey – here called route – may have different start and stop points (seq values)

The Solution

In the real case I found the min and max seq for each journey and added these as columns to my base table. This was all done in SQL 2014

CREATE TABLE #Journey(
[JourneyID] [int] NOT NULL,
[Route] [int] NOT NULL,
[seq] [int] NOT NULL,
[tme] [smalldatetime] NOT NULL,
[maxSeq] [int] NOT NULL,
[minSeq] [int] NOT NULL);

INSERT INTO #Journey
Values(1056975,20,2,’2015-06-03 09:34:00′,99,2),
(1056975,20,5,’2015-06-03 09:38:00′,99,2),
(1056975,20,6,’2015-06-03 09:39:00′,99,2),
(1056975,20,99,’2015-06-03 09:44:00′,99,2),
(1056975,20,99,’2015-06-03 09:45:00′,99,2),
(1056975,20,99,’2015-06-03 09:49:00′,99,2),
(1056975,20,99,’2015-06-03 09:53:00′,99,2),
(1056975,20,99,’2015-06-03 09:56:00′,99,2),
(1056975,20,99,’2015-06-03 09:57:00′,99,2),
(2471362,1,1,’2015-06-06 07:48:00′,99,1),
(2471362,1,1,’2015-06-06 07:49:00′,99,1),
(2471362,1,2,’2015-06-06 07:56:00′,99,1),
(2471362,1,5,’2015-06-06 07:57:00′,99,1),
(2471362,1,5,’2015-06-06 07:59:00′,99,1),
(2471362,1,8,’2015-06-06 08:05:00′,99,1),
(2471362,1,11,’2015-06-06 08:08:00′,99,1),
(2471362,1,14,’2015-06-06 08:15:00′,99,1),
(2471362,1,15,’2015-06-06 08:21:00′,99,1),
(2471362,1,99,’2015-06-06 08:23:00′,99,1)

;WITH journeyStart(JourneyID, [Route], seq, tme, RN)
as (
SELECT JourneyID, [Route], seq, tme, RN=row_number()
OVER (PARTITION BY JourneyID ORDER BY seq desc)
FROM #Journey WHERE seq = [minSeq])

SELECT JS.[Route], JS.seq as TrainSequenceStart, JS.tme as StartTime,

RJ2.seq as TrainSequenceEnd, RJ2.tme as EndTime, JT.JourneyTime as
[JourneyTime (minutes)]
FROM journeyStart as JS

CROSS APPLY (select top (1) RJe.*
FROM #Journey as RJe
where RJe.JourneyID = JS.JourneyID
AND RJe.[Route] = JS.[Route]
AND RJe.Seq = RJe.maxSeq
order by RJe.JourneyID, RJe.seq) as RJ2

CROSS APPLY (SELECT DateDiff(mi,JS.tme,RJ2.tme) as journeyTime) as JT

WHERE JS.RN = 1;

DROP TABLE #Journey;

The important point it in the 1st cross apply, RJe.Seq = RJe.maxSeq, which just says, get me the max seq value.
I added the second cross apply for the date calculation just to make the code easier to read.